y^2+26y-2432=0

Solution for y^2+26y-2432=0 equation:

y^2+26y-2432=0

a = 1; b = 26; c = -2432;
Δ = b2-4ac
Δ = 262-4·1·(-2432)
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10404}=102$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-102}{2*1}=\frac{-128}{2}
=-64
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+102}{2*1}=\frac{76}{2}
=38
$